7 + 24i

=> a^2 -b^2 + 2(a)(b)i =7 + 24i. Comparing both sides we get two equations a^2 - b^2 =7. And 2ab = 24 => ab = 12 => b =12/a. Now putting the value of b in equation 1 we get. a^2 - (12/a)^2 = 7 => a^2 -(144/a^2) = 7 => a^4 -144 = 7a^2 => a^4 -144 = 7a^2 => a^4 - 7 a^2 -144 = 0. Solving above quadratic equation we get. a^2 = (7+√(576+49))/2 or

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To avoid the risk of data loss, back up your data before you change your system … Question: Find All Complex Numbers Z Such That Z2=−7−24i, And Give Your Answer In The Form A+bi. Use The Square Root Symbol '√' Where Needed To Give An Exact Value For Your Answer. This problem has been solved! See the answer. Find all complex numbers z such that z 2 =−7−24i, and give your answer in the form a+bi.

5 amended by adding Section 7.24i as follows: 6 (20 ILCS 3805/7.24i new) 7 Sec. _7.24i. Homeowners Emergency Mortgage Assistance and 8 Counseling _Program.

Get an answer for 'what is the square root of the complex number 7-24i?' and find homework help for other Math questions at eNotes. 27 Nov 2020 Let `sqrt(-7-24i)=x+iy` Squaring both sides `-7-24i=(x+iy)^2` `x^2-y^2=-7` and ` 2xy=-24` `(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2` Square root both See that z=a+bi. Thus, z2=a2−b2+2abi.

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Share 6 Follow6. Himanshu , Meritnation Expert added an answer, 19. 7-24i \left(8 xoot\right) \left(a\right) ±\left(4-3i\right) \left(b\right)±\left(3-4i\right) \ left(c\right) ±\left(3+4i\right) \left(d\right)±\left(4+3i\right) 7 i or 2i √. __. 7 or (2 √.

-25 c. 22.956 d. -22.956 e. 527 11. (T/F) The following matrices are inverses of each other A- TA 5 91.8 = (-8 51 12. (T/F) If A is a 15x19 matrix and B is a 19x4 matrix, then you can multiply BxA 13.

25 b. -25 c. 22.956 d. -22.956 e. 527 11. (T/F) The following matrices are inverses of each other A- TA 5 91.8 = (-8 51 12.

5 amended by adding Section 7.24i as follows: 6 (20 ILCS 3805/7.24i new) 7 Sec. _____7.24i. Homeowners Emergency Mortgage Assistance and 8 Counseling _____Program. Jun 11, 2020 · z = -7 - 24i. z = r(cosΘ + isinΘ) where: r = √(7²+24²) = 25. and. Θ = arctan[(-24)/(-7)] = arctan(24/7) + π = 1.410π rad = 254° The real part is -7 [24]7.ai (full company name [24]7.ai, Inc.) is a customer experience software and services company based in California that uses artificial intelligence and machine learning to understand consumer intent.

978 views ·. View upvotes. Get an answer for 'what is the square root of the complex number 7-24i?' and find homework help for other Math questions at eNotes. 27 Nov 2020 Let `sqrt(-7-24i)=x+iy` Squaring both sides `-7-24i=(x+iy)^2` `x^2-y^2=-7` and ` 2xy=-24` `(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2` Square root both See that z=a+bi. Thus, z2=a2−b2+2abi. Setting it equal, we get. a2−b2=72ab= −24.

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Find the modulus and argument of $(-7+24i)$ giving your value of the argument in radian correct to 3 significant figures. Modulus of $(-7+24i)= \sqrt{(-7)^2+{24}^2} =25$ Arg $(-7+24i)=\tan^{-1}\big(\displaystyle\frac{24}{-7}\big) =1.85$ rad. I don’t know how to solve the second part of the question: Use de Moivre’s theorem to find the value of the real part of $(-7+24i)^8$, correct to 3 …

Same as 24/7. Webster's Revised Unabridged Find all complex numbers z such that z 2 =−7−24i, and give your answer in the form a+bi.Use the square root symbol '√' where needed to give an exact value for your answer. 10.|-7+24i| a. 25 b. -25 c. 22.956 d. -22.956 e.

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c) 17. d) 25 . Thanks! Update: So that would be . sqrt(49+ 576) sqrt (625) 25.

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